Raccoon Update XIV - All Are Welcome In The Critter Cafe

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Message 1262851 - Posted: 21 Jul 2012, 6:27:11 UTC - in response to Message 1262844.  

The important thing is of regardless of when or if the cord breaks, the Raccoon will have access to the food.


I think you are right Soft.
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Message 1262855 - Posted: 21 Jul 2012, 6:47:13 UTC - in response to Message 1262825.  

I remember Luke having a Math thread. Not my forte, but I will be looking forward to the answer Esme.

Sum of clockwise torque = sum of anti-clockwise torque:

So taking moments (torque) around the pivot,

{weight of the raccoon}*x + {weight of beam}* 1.1 m + {weight of basket}* 2.2m = {tension in cord}*sin 72 *2.2m

(as Gary correctly pointed out the raccoon's centre of mass is where it's weight acts. 91N*sin72 is the component of the tension force acting perpendicular to the beam)

9.8m/s^2*8kg*x + 9.8m/s^2*2kg*1.1m + 9.8m/s^2*1.3kg*2.2m = 91N*2.2m*sin72

so x= {91*2.2*sin72-9.8*(1.3*2.2+2*1.1)}/8*9.8 = 1.8 m





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Message 1262858 - Posted: 21 Jul 2012, 6:54:50 UTC

Es, Gary
Can you tranlate that to us Math changelled?
Please!
Spell checker not used either.
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Message 1262913 - Posted: 21 Jul 2012, 12:22:04 UTC - in response to Message 1262899.  

I followed it OK, but I had to convert stuff to imperial first. I cant be doing with all this continental Newtons and KG stuff. This is really a simple moments around a pivot question, what made it interesting was the 72 degree angle added.

In laymans terms, the weight of the beam and the weight of the basket combine to produce a tension upon the rope. As the raccoon travels along the beam, it's weight will cause an extra tension on the rope, and the further it travels towards the food, the tension will increase. At some point the tension upon the rope will be more than the rope can withstand, and it will break. This can simply be calculated, by taking moments around the pivot as Es has done.

Adding in torque just muddies the answer, although it is technically correct. You could also say that the system is in equilibrium, until the rope breaks.



Then a 2nd Raccoon can come out and get the spilled food which is presumably on the ground by this time.
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Message 1262914 - Posted: 21 Jul 2012, 12:27:28 UTC - in response to Message 1262855.  


9.8m/s^2*8kg*x + 9.8m/s^2*2kg*1.1m + 9.8m/s^2*1.3kg*2.2m = 91N*2.2m*sin72

so x= {91*2.2*sin72-9.8*(1.3*2.2+2*1.1)}/8*9.8 = 1.8 m


It's hard to argue with that formula, but the way I figured it, the answer is 69.



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Message 1262974 - Posted: 21 Jul 2012, 16:23:12 UTC

The right answer is the raccoon backs out so his claws are in the correct direction, then slaps his tail down on the beam thus breaking the string, and he continues down into the bucket and gorges himself.

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Message 1262990 - Posted: 21 Jul 2012, 17:01:32 UTC - in response to Message 1262899.  

...

Adding in torque just muddies the answer, although it is technically correct. You could also say that the system is in equilibrium, until the rope breaks.



Yes, the question was an equilibrium one. I mention torque because that is how they prefer to term it over here. Whereas in the UK we are more used to calling them moments.

I'm still learning to speak Canadian properly. I also get very muddled with the symbols because the Physics 12 syllabus here uses different symbols from the ones I've used for years in the UK. I'm trying to use the ones in the book so as not to confuse the students, but my hands keep writing the ones I am used to on the board even though my brain tells it not too, LOL!
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Message 1262991 - Posted: 21 Jul 2012, 17:02:24 UTC - in response to Message 1262974.  

The right answer is the raccoon backs out so his claws are in the correct direction, then slaps his tail down on the beam thus breaking the string, and he continues down into the bucket and gorges himself.

LOL. That sounds more like an Impulse problem.
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Message 1262995 - Posted: 21 Jul 2012, 17:08:46 UTC - in response to Message 1262991.  

The right answer is the raccoon backs out so his claws are in the correct direction, then slaps his tail down on the beam thus breaking the string, and he continues down into the bucket and gorges himself.

LOL. That sounds more like an Impulse problem.

Impulse power is here...

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Message 1263010 - Posted: 21 Jul 2012, 17:33:18 UTC - in response to Message 1262828.  

I am SOOOOOO glad to see I am not the only one that cannot supply an answer. . .


Me neither. I was never good at math...
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Message 1263022 - Posted: 21 Jul 2012, 17:52:39 UTC - in response to Message 1263010.  

I am SOOOOOO glad to see I am not the only one that cannot supply an answer. . .


Me neither. I was never good at math...

My Mom said I was good at math, I can even do some in My head, division takes longer or I just can't do...
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Message 1263032 - Posted: 21 Jul 2012, 18:17:03 UTC - in response to Message 1262980.  
Last modified: 21 Jul 2012, 18:17:33 UTC

The question was not how can the Raccoon get the food, but when will the rope break. How about this one.

An irate Raccoon nibbles Erics toenails at 1mm per month. Eric's toenails grow at 1.5mm per month. if his toenails start of at 10mm long, and then break off when they are 15mm long back to 5mm long. How, how long will it take them to grow back to 10mm long?

Answers on a post card to Angela Korpela C/O Seti@Home.


Let's see... let me double check.... add 3... divide by 7.3... carry the one... yup... 69!


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Message 1263062 - Posted: 21 Jul 2012, 19:53:00 UTC

I went camping recently. We had a visitor in the camp site. I finally got a few pictures of it while we were packing up to go. We named it clockwise as that is the direction it proceeded through camp every evening.







It walked up and sniffed my feet at one while I was shooting pictures.


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Message 1263069 - Posted: 21 Jul 2012, 20:18:13 UTC

**BREAKING NEWS**

A critter has been spotted at the Baikonur cosmodrome in Kazakhstan (vid eight and a half minutes long). The Gopher, it is rumoured, has apparently been making plans to head a critter expedition to space. Officials have stated that "there's nothing to worry about", and that "the wildlife nearby have no such plans".

However locals have noted the erection of a new structure. "Nobody knows what it is" said John Smith, 38, "they're definitely up to something". Another local, Derek Jacobs, 54, (has mortgaged house, wife, three kids and is having an affair with his secretary), said that "there's been at lot of activity around this new structure", "but none of the markings have been of the "Acme" company, so there might be something to this".

More news after these messages.

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Message 1263076 - Posted: 21 Jul 2012, 20:39:35 UTC - in response to Message 1263069.  

**BREAKING NEWS**

A critter has been spotted at the Baikonur cosmodrome in Kazakhstan (vid eight and a half minutes long). The Gopher, it is rumoured, has apparently been making plans to head a critter expedition to space. Officials have stated that "there's nothing to worry about", and that "the wildlife nearby have no such plans".

However locals have noted the erection of a new structure. "Nobody knows what it is" said John Smith, 38, "they're definitely up to something". Another local, Derek Jacobs, 54, (has mortgaged house, wife, three kids and is having an affair with his secretary), said that "there's been at lot of activity around this new structure", "but none of the markings have been of the "Acme" company, so there might be something to this".

More news after these messages.

And in response...


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Message 1263082 - Posted: 21 Jul 2012, 21:00:23 UTC - in response to Message 1263076.  

**BREAKING NEWS**

A critter has been spotted at the Baikonur cosmodrome in Kazakhstan (vid eight and a half minutes long). The Gopher, it is rumoured, has apparently been making plans to head a critter expedition to space. Officials have stated that "there's nothing to worry about", and that "the wildlife nearby have no such plans".

However locals have noted the erection of a new structure. "Nobody knows what it is" said John Smith, 38, "they're definitely up to something". Another local, Derek Jacobs, 54, (has mortgaged house, wife, three kids and is having an affair with his secretary), said that "there's been at lot of activity around this new structure", "but none of the markings have been of the "Acme" company, so there might be something to this".

More news after these messages.

And in response...

Hahahahahaha, good grief has that hit my funny bone :)

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Message 1263097 - Posted: 21 Jul 2012, 21:31:10 UTC

Great pics John.

Thanks for sharing.



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Message 1263165 - Posted: 22 Jul 2012, 0:23:35 UTC

Just discovered Es' raccoon problem, having been traipsing through airports on 3 continents for the last few days. Very well presented. What level are your students? I think we did something like this in Alberta Grade 12 way back in the last century, and definitely did a lot of those in first year engineering.

Engineers (on both sides of the pond) use the terms moment and torque interchangeably, although strictly speaking torque is a moment of force. (You can have moments of mass, moments of area, etc.) Es' solution correctly converted the masses to forces, giving us moments of force - or torque. Alternatively, you could have summed a moment of mass, and converted the sum into tension in the upper cord, using the local gravitational strength. This gives a more general equation that could be applied, for example, on Mars (just watched John Carter on the plane), or could also be applied in an accelerating frame of reference. One would have to wonder what a raccoon would be doing on Mars, or in an accelerating frame of reference. That could be their creative literature assignment.

One minor picky point: you can't state "how far out the raccoon goes" without stating a reference point to use on the raccoon, and a reference point somewhere on the fixed structure. Using the c.g. is the easiest, but for extra points: assume a reference point on the raccoon's nose, 16.2 cm in front of the c.g., and let the location of said reference point be 0 when the nose first crosses onto the beam. Now rewrite the equation.

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Message 1263167 - Posted: 22 Jul 2012, 0:37:20 UTC - in response to Message 1262844.  

The important thing is of regardless of when or if the cord breaks, the Raccoon will have access to the food.


But shall he ever get there?

Some do not understand the implications of the mathematical question.

Everthing is in play......the beam, it's weight, the fact that is anchored on one end. The angle of the supporting chord....this has a bearing. We have to assume that the midweight of hungry Rocky raccoon is as pictu
I do not, myself have the mathematical knowledge to solve the problem.
I only know the things that play into it.
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Message 1263421 - Posted: 22 Jul 2012, 17:51:42 UTC - in response to Message 1263097.  

Great pics John.

Thanks for sharing.


+2
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