"Simple" Maths Problems II

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Profile jason_gee
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Message 780658 - Posted: 8 Jul 2008, 10:05:29 UTC - in response to Message 780638.  


Q4 (1/2 Point): What is:
(1267+8-456x2)÷(243x3.5)=???

--> 363 / 850.5
= 726 / 1701
= 242 / 567
~= 0.4268
"Living by the wisdom of computer science doesn't sound so bad after all. And unlike most advice, it's backed up by proofs." -- Algorithms to live by: The computer science of human decisions.
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Message 780662 - Posted: 8 Jul 2008, 10:16:14 UTC - in response to Message 780638.  
Last modified: 8 Jul 2008, 10:26:21 UTC

Well Done to Jason! Winterknight following close behind.

Standings:
1. Fred - 1 Point
2. The Gas Giant - 1/2 Point
3. Jason Gee - 1/2 Point

Q4 (1/2 Point): What is:
(1267+8-456x2)÷(243x3.5)=???

Luke.


0.4268(077)
Sorry, answer already given.
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Luke
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Message 780810 - Posted: 8 Jul 2008, 22:18:23 UTC - in response to Message 780662.  

Well Done to Jason! Winterknight following close behind.

Standings:
1. Fred - 1 Point
2. The Gas Giant - 1/2 Point
3. Jason Gee - 1/2 Point

Q4 (1/2 Point): What is:
(1267+8-456x2)÷(243x3.5)=???

Luke.


0.4268(077)
Sorry, answer already given.


Don't worry 'bout it, Fred!!! It's nice to have you here!
Jason Gee wins Question 4, well done!

Question 4 Answer: 0.4268

Standings:
1. Fred - 1 Point
2. Jason Gee - 1 Point
3. The Gas Giant - 1/2 Point
4. TBD...

Question 5 (1/2 Point):

(876x2.4)+(1976-432x1.2)=???

Luke.
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Message 780823 - Posted: 8 Jul 2008, 22:39:13 UTC

3560
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Luke
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Message 781067 - Posted: 9 Jul 2008, 6:57:11 UTC - in response to Message 780823.  
Last modified: 9 Jul 2008, 6:58:08 UTC

3560


Well Done Gas Giant! Can you solve this one?...

Standings:
1. Fred - 1 Point
2. Jason Gee - 1 Point
3. The Gas Giant - 1 Point
4. TBD...

Question 6 (1 Point):
On the first day of a new job, a colleague invites you around for a barbecue. As the two of you arrive at his home, a young boy throws open the door to welcome his father. “My other two kids will be home soon!” remarks your colleague.

Waiting in the kitchen while your colleague gets some drinks from the basement, you notice a letter from the principal of the local school tacked to the noticeboard. “Dear Parents,” it begins, “This is the time of year when I write to all parents, such as yourselves, who have a girl or girls in the school, asking you to volunteer your time to help the girls' soccer team.” “Hmmm,” you think to yourself, “clearly they have at least one of each!”

This, of course, leaves two possibilities: two boys and a girl, or two girls and a boy. Are these two possibilities equally likely, or is one more likely than the other?

Note: This is not a trick puzzle. You should assume all things that it seems you're meant to assume, and not assume things that you aren't told to assume. If things can easily be imagined in either of two ways, you should assume that they are equally likely. For example, you may be able to imagine a reason that a colleague with two boys and a girl would be more likely to have invited you to dinner than one with two girls and a boy. If so, this would affect the probabilities of the two possibilities. But if your imagination is that good, you can probably imagine the opposite as well. You should assume that any such extra information not mentioned in the story is not available.

Luke.
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Message 781123 - Posted: 9 Jul 2008, 10:18:54 UTC

Hmmm....a stab in the dark says that the probability is higher that in total there is one boy and two girls. Assumptions here are:

1. Something in the way the father says, my other two kids will be home soon. Maybe they're at the girls soccer practice.

2. Girls' soccer team v girls soccer team. Does this imply they have 2 girls....

Anywho....
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Message 781146 - Posted: 9 Jul 2008, 11:37:59 UTC
Last modified: 9 Jul 2008, 11:50:57 UTC

Given one boy, the remaining children could be either boy & girl, or two girls, so the possible combinations are:

Boy Girl Boy (1/3)
Boy Boy Girl (1/3)
Boy Girl Girl (1/3)

So there's two thirds chance the colleague has two boys & a girl, and one third chance the colleague has one boy and two girls.

Jason

[P.S. Lovely story about soccer teams and stuff, but I think it has little bearing on the possibilities other than to say at least one of the remaining kids is a girl]
"Living by the wisdom of computer science doesn't sound so bad after all. And unlike most advice, it's backed up by proofs." -- Algorithms to live by: The computer science of human decisions.
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Message 781256 - Posted: 9 Jul 2008, 21:17:18 UTC - in response to Message 781146.  

Given one boy, the remaining children could be either boy & girl, or two girls, so the possible combinations are:

Boy Girl Boy (1/3)
Boy Boy Girl (1/3)
Boy Girl Girl (1/3)

So there's two thirds chance the colleague has two boys & a girl, and one third chance the colleague has one boy and two girls.

Jason

[P.S. Lovely story about soccer teams and stuff, but I think it has little bearing on the possibilities other than to say at least one of the remaining kids is a girl]

Ahh..I'd have to agree with that.
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Message 781317 - Posted: 10 Jul 2008, 16:22:19 UTC

You could have three boys, because the teacher did not know difference between Lesley and Leslie.
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Message 781342 - Posted: 10 Jul 2008, 17:43:31 UTC - in response to Message 781317.  

You could have three boys, because the teacher did not know difference between Lesley and Leslie.

I think they also have an ambiguous gender soccer team :D
"Living by the wisdom of computer science doesn't sound so bad after all. And unlike most advice, it's backed up by proofs." -- Algorithms to live by: The computer science of human decisions.
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Message 781385 - Posted: 10 Jul 2008, 21:21:28 UTC

Well Done to Jason Gee!... 1 Point... He takes the lead...

Standings:
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. TBD...

Question 7 (1/2 Point):

(7x8*6)+(8x7(cubed)+15)x0.8=?

Luke.
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Message 781400 - Posted: 10 Jul 2008, 21:46:04 UTC - in response to Message 781385.  

Well Done to Jason Gee!... 1 Point... He takes the lead...

Standings:
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. TBD...

Question 7 (1/2 Point):

(7x8*6)+(8x7(cubed)+15)x0.8=?

Luke.

Can you be consistent with symbols, please? Is mutiplication "x" or "*"?

F.
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Luke
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Message 781404 - Posted: 10 Jul 2008, 21:53:54 UTC - in response to Message 781400.  

Well Done to Jason Gee!... 1 Point... He takes the lead...

Standings:
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. TBD...

Question 7 (1/2 Point):

(7x8*6)+(8x7(cubed)+15)x0.8=?

Luke.

Can you be consistent with symbols, please? Is mutiplication "x" or "*"?

F.


Multiplication = x
Division = *

Luke.
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Fred W
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Message 781408 - Posted: 10 Jul 2008, 21:57:32 UTC - in response to Message 781404.  

Well Done to Jason Gee!... 1 Point... He takes the lead...

Standings:
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. TBD...

Question 7 (1/2 Point):

(7x8*6)+(8x7(cubed)+15)x0.8=?

Luke.

Can you be consistent with symbols, please? Is mutiplication "x" or "*"?

F.


Multiplication = x
Division = *

Luke.

Hmmm. Thanks. First time I've seen that symbol used for division. In that case, shouldn't this question be worth 1*2 Point?

F.
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Luke
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Message 781410 - Posted: 10 Jul 2008, 22:00:32 UTC - in response to Message 781408.  

Well Done to Jason Gee!... 1 Point... He takes the lead...

Standings:
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. TBD...

Question 7 (1/2 Point):

(7x8*6)+(8x7(cubed)+15)x0.8=?

Luke.

Can you be consistent with symbols, please? Is mutiplication "x" or "*"?

F.


Multiplication = x
Division = *

Luke.

Hmmm. Thanks. First time I've seen that symbol used for division. In that case, shouldn't this question be worth 1*2 Point?

F.


Lol, 1/2 refers to the fraction...
In NZ we use +,-,x,*...

Luke.
- Luke.
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Message 781414 - Posted: 10 Jul 2008, 22:06:56 UTC - in response to Message 781410.  

Well Done to Jason Gee!... 1 Point... He takes the lead...

Standings:
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. TBD...

Question 7 (1/2 Point):

(7x8*6)+(8x7(cubed)+15)x0.8=?

Luke.

Can you be consistent with symbols, please? Is mutiplication "x" or "*"?

F.


Multiplication = x
Division = *

Luke.

Hmmm. Thanks. First time I've seen that symbol used for division. In that case, shouldn't this question be worth 1*2 Point?

F.


Lol, 1/2 refers to the fraction...
In NZ we use +,-,x,*...

Luke.

Interesting. I wonder how widespread that usage is? I have only ever come across the * used for multiplication.

BTW, I believe the answer to be 2214.933333...

F.
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Message 781431 - Posted: 10 Jul 2008, 22:35:35 UTC - in response to Message 781385.  

Well Done to Jason Gee!... 1 Point... He takes the lead...

Standings:
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. TBD...

Question 7 (1/2 Point):

(7x8*6)+(8x7(cubed)+15)x0.8=?

Luke.


2216.53333...
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Fred W
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Message 781438 - Posted: 10 Jul 2008, 22:45:59 UTC - in response to Message 781431.  

Well Done to Jason Gee!... 1 Point... He takes the lead...

Standings:
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. TBD...

Question 7 (1/2 Point):

(7x8*6)+(8x7(cubed)+15)x0.8=?

Luke.


2216.53333...

Good spot, JD. That's what comes of trying to do it in my head :(

F.
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Luke
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Message 781829 - Posted: 12 Jul 2008, 20:47:41 UTC

Well Done to JDWhale! 1/2 Point to you...

Standings
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. JDWhale - 1/2 Point
5. TBD...

As to be consistent to American markup...
Addition = +
Subtraction = -
Multiplication = *
Division = /


Question 8: 1/2 a Point:

(220*3.4/18)*(821/13)=?

Luke.



- Luke.
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Message 781873 - Posted: 12 Jul 2008, 21:44:28 UTC - in response to Message 781829.  

Well Done to JDWhale! 1/2 Point to you...

Standings
1. Jason Gee - 2 Point
2. Fred - 1 Point
3. The Gas Giant - 1 Point
4. JDWhale - 1/2 Point
5. TBD...

As to be consistent to American markup...
Addition = +
Subtraction = -
Multiplication = *
Division = /


Question 8: 1/2 a Point:

(220*3.4/18)*(821/13)=?

Luke.



Q8: 2624.2678 to 4dp.

F.
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