Each FFT length F has an associated duration D(F). If a spike of that FFT length is found during an observation shorter than D(F), it's probably RFI.
FFT bins begin at regularly-spaced times. An observation of duration 2*D(F) contains at least one FFT bin in its entirety, and an observation of duration 3*D(F) contains two.
Multiplets have at least two time-disjoint detections. Thus to find a multiplet composed of spikes of FFT length F in a pixel P, our observations of P must include two disjoint intervals of duration D(F). This is always the case if P has
| FFT duration | # pixels, strong | % of pixels, strong | # pixels, weak | % of pixels, weak |
|---|---|---|---|---|
| 8 | 15399958 | 100 | 15399958 | 100 |
| 16 | 15399958 | 100 | 15399958 | 100 |
| 32 | 15399958 | 100 | 15399958 | 100 |
| 64 | 15399958 | 100 | 15399958 | 100 |
| 128 | 15399958 | 100 | 15399958 | 100 |
| 256 | 15399958 | 100 | 15399958 | 100 |
| 512 | 15358403 | 99.730162 | 15362358 | 99.755843 |
| 1024 | 15003663 | 97.426649 | 15243071 | 98.98125 |
| 2048 | 14401001 | 93.513249 | 14922394 | 96.898927 |
| 4096 | 12057337 | 78.29461 | 14089389 | 91.489788 |
| 8192 | 7804281 | 50.677288 | 10933704 | 70.998272 |
| 16384 | 6554602 | 42.562467 | 7460499 | 48.444931 |
| 32768 | 3300343 | 21.430857 | 5849600 | 37.984519 |
| 65536 | 372334 | 2.41776 | 1788447 | 11.613324 |
| 131072 | 344996 | 2.24024 | 365336 | 2.372318 |
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