"Simple" Maths Problems II
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"Simple" Maths Problems II
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 Mumps [MM]  Send message Joined: 11 Feb 08 Posts: 4454 Credit: 100,893,853 RAC: 30 
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Question 26 Part 2 (1 Point) : What is the area of an equalateral pentagon of side 1? Again, no expressions in trigonometric functions... "Simple" maths and "trigonometric functions" never went together in my book...  ID: 797607 ·  |
jason_gee  Send message Joined: 24 Nov 06 Posts: 7489 Credit: 91,093,184 RAC: 0 
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Question 26 Part 2 (1 Point) : What is the area of an equalateral pentagon of side 1? Again, no expressions in trigonometric functions... (Hint: Solve Q26 Part 1 first) My calculation (based on the answer for pt 1): 1.92355221125 [probably wrong now I look again, but oh well...] [EDIT: New Answer! 1.3471044225 ] "Living by the wisdom of computer science doesn't sound so bad after all. And unlike most advice, it's backed up by proofs." -- Algorithms to live by: The computer science of human decisions. ID: 797745 · |
W-K 666  Send message Joined: 18 May 99 Posts: 19065 Credit: 40,757,560 RAC: 67 
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Luke, Apologies for not taking part, but usually, with my usual sense of bad timing, when I have had time the questions have already been answered. Andy But you can try this ID: 797756 · |
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Lanisa Send message Joined: 5 Jun 99 Posts: 25 Credit: 688,811 RAC: 0 
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JD is right. it's ~1,7204774 * side_length² ID: 797864 · |
Luke  Send message Joined: 31 Dec 06 Posts: 2546 Credit: 817,560 RAC: 0 
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Luke, No worries WinterKnight! Great link you've got there! I liked Questions 3 & 6! For question 3 have a look at: Birthday Paradox @ Mumps: It's becoming harder and harder the find problems!!! So I suppose Simple & Trigonometric Functions go hand in hand... Well Done to JD! Who scored the point for this question! Standings: 1. Jason Gee - 6 1/2 Points 2. Fred - 4 1/2 Points 3. BeefDog - 3 1/2 Points 4. JDWhale - 3 1/2 Points 5. Gas Giant - 1 Point 6. Dominique - 1 Point 7. Zach Parker - 1 Point 8. Erni - 1 Point 9. Lanisa - 1 Point 10. Sarge - 1/2 Point 11. TBD... Now for the finale in Q26... Question 26 Part 3 (1 Point) : What is the volume of a dodecahedron with side (of pentagon) equal to 1? Hint: Solve P2, P1 first.... Luke. - Luke. ID: 797954 · |
bobby  Send message Joined: 22 Mar 02 Posts: 2866 Credit: 17,789,109 RAC: 3
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Luke, About 7.6631189606246319687160539202797 :) I think you'll find it's a bit more complicated than that ... 
ID: 798035 · |
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Mumps [MM] Send message Joined: 11 Feb 08 Posts: 4454 Credit: 100,893,853 RAC: 30
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@ Mumps: It's becoming harder and harder the find problems!!! So I suppose Simple & Trigonometric Functions go hand in hand... Well, I'm not complaining about the problems. :-) My timing is just atrocious though. Never can get to the thread before someone else posts an answer.  ID: 798124 · |
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Luke Send message Joined: 31 Dec 06 Posts: 2546 Credit: 817,560 RAC: 0
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@ Mumps: It's becoming harder and harder the find problems!!! So I suppose Simple & Trigonometric Functions go hand in hand... Not to worry, I believe some people have an edge on this thread by subscribing to it... You'll get a point eventually. @ Bobby, close enough! You get the point! Standings: 1. Jason Gee - 6 1/2 Points 2. Fred - 4 1/2 Points 3. BeefDog - 3 1/2 Points 4. JDWhale - 3 1/2 Points 5. Gas Giant - 1 Point 6. Dominique - 1 Point 7. Zach Parker - 1 Point 8. Erni - 1 Point 9. Lanisa - 1 Point 10. Bobby - 1 Point 11. Sarge - 1/2 Point 12. TBD... Another Question coming soon. - Luke. ID: 798144 · |
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Luke Send message Joined: 31 Dec 06 Posts: 2546 Credit: 817,560 RAC: 0
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Question 27 (1 Point) : A student sends the following letter to his parents: SEND +MORE ----- MONEY Each letter in this letter represents a specific and unique integer. What does each letter stand for? - Luke. ID: 798476 · |
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bobby Send message Joined: 22 Mar 02 Posts: 2866 Credit: 17,789,109 RAC: 3
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Question 27 (1 Point) : A student sends the following letter to his parents: O=0, M=1, Y=2, E=5, N=6, D=7, R=8, S=9 9567 +1085 ----- 10652 I think you'll find it's a bit more complicated than that ...
ID: 798512 · |
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Fred W Send message Joined: 13 Jun 99 Posts: 2524 Credit: 11,954,210 RAC: 0
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Question 27 (1 Point) : A student sends the following letter to his parents: Congrats (Grrrrr!) bobby. I was just about to post the same answer ;( F. 
ID: 798537 · |
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Luke Send message Joined: 31 Dec 06 Posts: 2546 Credit: 817,560 RAC: 0
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Yes, well done Bobby, I see you have the correct answers! 1 Point to you... Standings: 1. Jason Gee - 6 1/2 Points 2. Fred - 4 1/2 Points 3. BeefDog - 3 1/2 Points 4. JDWhale - 3 1/2 Points 5. Bobby - 2 Points 6. Gas Giant - 1 Point 7. Dominique - 1 Point 8. Zach Parker - 1 Point 9. Erni - 1 Point 10. Lanisa - 1 Point 11. Sarge - 1/2 Point 12. TBD... Question 28 (1/2 Point): 14*295/45+12*12(cubed)=? Luke. - Luke. ID: 799538 · |
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Fred W Send message Joined: 13 Jun 99 Posts: 2524 Credit: 11,954,210 RAC: 0
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Yes, well done Bobby, I see you have the correct answers! 1 Point to you... 20827.777777777... F.
ID: 799552 · |
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BeefDog Send message Joined: 9 Feb 00 Posts: 91 Credit: 146,476 RAC: 0 
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ID: 799553 · |
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jason_gee Send message Joined: 24 Nov 06 Posts: 7489 Credit: 91,093,184 RAC: 0
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Same answer here ... oooooh 'e's catchin up! The timezones could lose the lead for me soon! ;D "Living by the wisdom of computer science doesn't sound so bad after all. And unlike most advice, it's backed up by proofs." -- Algorithms to live by: The computer science of human decisions. ID: 799630 · |
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Luke Send message Joined: 31 Dec 06 Posts: 2546 Credit: 817,560 RAC: 0
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Well Done to Fred! That's 1/2 a point to you.... oh... watch out Jason... Fred's catching up... Standings: 1. Jason Gee - 6 1/2 Points 2. Fred - 5 Points 3. BeefDog - 3 1/2 Points 4. JDWhale - 3 1/2 Points 5. Bobby - 2 Points 6. Gas Giant - 1 Point 7. Dominique - 1 Point 8. Zach Parker - 1 Point 9. Erni - 1 Point 10. Lanisa - 1 Point 11. Sarge - 1/2 Point 12. TBD... Question 29 (1 Point): In blackjack if the dealer is showing an ace you make "take insurance" or bet that his/her other card is a ten. A winning bet pays 2:1 (win $2 for every $1 bet, keeping original bet). What is the house advantage in this bet? How many non-tens would you have to remove from a single deck game to make it a fair bet? Assume you know nothing about the cards that have already been played (including the dealer's ace and your own) Luke. - Luke. ID: 801210 · |
kittyman     Send message Joined: 9 Jul 00 Posts: 51468 Credit: 1,018,363,574 RAC: 1,004
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Well Done to Fred! That's 1/2 a point to you.... oh... watch out Jason... Fred's catching up... Question...... I toss back a shot, and tell the dealer to **** off and flip me a card..... What are the odds that he will call house security within 2 minutes or less...... At an ambient of 70f, at 3:00am or later (Vegas time)....(I have two pair, but of course, he doesn't know that....)...with the faux Elvis show starting in 2 minutes, and someone has just kicked the jackpot on the nickels for 5 grand........on Tuesday. "Freedom is just Chaos, with better lighting." Alan Dean Foster 
ID: 801216 · |
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Luke Send message Joined: 31 Dec 06 Posts: 2546 Credit: 817,560 RAC: 0
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Well Done to Fred! That's 1/2 a point to you.... oh... watch out Jason... Fred's catching up... So many ***** variables (phhh...)... I'll knock back a shot now and assume you mean under the usual "mathematical" conditions.... yikes... - Luke. ID: 801217 · |
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kittyman Send message Joined: 9 Jul 00 Posts: 51468 Credit: 1,018,363,574 RAC: 1,004
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LOL.....That means you mean 'real life' conditions.....eh?Well Done to Fred! That's 1/2 a point to you.... oh... watch out Jason... Fred's catching up... BTW....it is a 'kobayahsi maru' scenario...........you cannot win unless you change the parameters.......LOL. Meaning security is already focused on the drunk raising caine in the coat room....and Spock has passed out in the parking lot......but you could not have known that.....there was no way to win...... "Freedom is just Chaos, with better lighting." Alan Dean Foster
ID: 801220 · |
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jason_gee Send message Joined: 24 Nov 06 Posts: 7489 Credit: 91,093,184 RAC: 0
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Question 29 (1 Point): In blackjack if the dealer is showing an ace you make "take insurance" or bet that his/her other card is a ten. A winning bet pays 2:1 (win $2 for every $1 bet, keeping original bet). What is the house advantage in this bet? How many non-tens would you have to remove from a single deck game to make it a fair bet? Assume you know nothing about the cards that have already been played (including the dealer's ace and your own) Oy!, that's two questions ;D part one: (16/52)*$3 payoff = $0.923 therefore house advantage on $1 bet is : $1 - $0.923 = $0.077 ... (7.7% house advantage) part two: 16 tens out of however many cards remaining must equal one third to be a fair bet: 16*3 = 48, therefore four non-ten cards must be removed from the 52 card deck to be fair. "Living by the wisdom of computer science doesn't sound so bad after all. And unlike most advice, it's backed up by proofs." -- Algorithms to live by: The computer science of human decisions. ID: 801225 · |
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