For that question, I will award JD & Jason a 1/2 Point.... Well Done both of you!

Standings:
1. Jason Gee - 4 Points
2. Fred - 1 1/2 Point
3. The Gas Giant - 1 Point
4. JDWhale - 1 Point
5. TBD...

Question 12 (1 Point) : Four people need to cross a bridge at night. The bridge is only strong enough to hold at most two people at once. Because it is night a flashlight must be used for all crossings. It takes person A ten minutes to cross, person B five minutes, person C two minutes, and person D one minute. If two cross at the same time they must walk at the slower man's pace. How can you get everyone across in 17 minutes?

Luke.

Have you indicated there's only one flash light?
If A or B, then C and D have flash lights, then you could have A and B cross, then C alone, then D alone. C is very heavy, so that's why C and D did not cross at the same time. Kobyashi Maru.

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Capitalize on this good fortune, one word can bring you round ... changes.

For that question, I will award JD & Jason a 1/2 Point.... Well Done both of you!

Standings:
1. Jason Gee - 4 Points
2. Fred - 1 1/2 Point
3. The Gas Giant - 1 Point
4. JDWhale - 1 Point
5. TBD...

Question 12 (1 Point) : Four people need to cross a bridge at night. The bridge is only strong enough to hold at most two people at once. Because it is night a flashlight must be used for all crossings. It takes person A ten minutes to cross, person B five minutes, person C two minutes, and person D one minute. If two cross at the same time they must walk at the slower man's pace. How can you get everyone across in 17 minutes?

Luke.

A & D cross together (10 minutes)
C & D cross together, opposite directions (2 minutes)
B & D cross together (5 minutes)

D carries flashlight on all crossings

total = 17 minutes

Question 12 (1 Point) : Four people need to cross a bridge at night. The bridge is only strong enough to hold at most two people at once. Because it is night a flashlight must be used for all crossings. It takes person A ten minutes to cross, person B five minutes, person C two minutes, and person D one minute. If two cross at the same time they must walk at the slower man's pace. How can you get everyone across in 17 minutes?

Luke.

First, C and D cross together and C returns (4 minutes).
Second, A and B cross together and D returns (11 minutes).
Third, C and D cross together (2 minutes).
4+11+2=17

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For that question, I will award JD & Jason a 1/2 Point.... Well Done both of you!

Standings:
1. Jason Gee - 4 Points
2. Fred - 1 1/2 Point
3. The Gas Giant - 1 Point
4. JDWhale - 1 Point
5. TBD...

Question 12 (1 Point) : Four people need to cross a bridge at night. The bridge is only strong enough to hold at most two people at once. Because it is night a flashlight must be used for all crossings. It takes person A ten minutes to cross, person B five minutes, person C two minutes, and person D one minute. If two cross at the same time they must walk at the slower man's pace. How can you get everyone across in 17 minutes?

Luke.

A & D cross together (10 minutes)
C & D cross together, opposite directions (2 minutes)
B & D cross together (5 minutes)

D carries flashlight on all crossings

total = 17 minutes

Sorry, JD: That means C is crossing without (the only, I assume) flashlight. Also assuming single-plank bridge with no hand-rails so big splash...

F.

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More Kobyashi Maru.
As D heads towards C, C has light. As they pass, C starts walking backwards, but very carefully.
Again, where is it said there's only one flashlight?

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Capitalize on this good fortune, one word can bring you round ... changes.

Sorry, JD: That means C is crossing without (the only, I assume) flashlight. Also assuming single-plank bridge with no hand-rails so big splash...

F.

C & D crossing simultaneously in opposite directions with D carrying the requisite flashlight conforms to all the rules and also lowers cumulative distance (6 vs. 8 bridge lengths).

Rules only state that if two people cross at the same time they must go at slower persons pace and the flashlight is used, not that both people are going the same direction.

Please, no assumptions.

Cheers,
JDWhale

For that question, I will award JD & Jason a 1/2 Point.... Well Done both of you!

Standings:
1. Jason Gee - 4 Points
2. Fred - 1 1/2 Point
3. The Gas Giant - 1 Point
4. JDWhale - 1 Point
5. TBD...

Question 12 (1 Point) : Four people need to cross a bridge at night. The bridge is only strong enough to hold at most two people at once. Because it is night a flashlight must be used for all crossings. It takes person A ten minutes to cross, person B five minutes, person C two minutes, and person D one minute. If two cross at the same time they must walk at the slower man's pace. How can you get everyone across in 17 minutes?

Luke.

C picks up flashlight
C and D cross (2 mins)
C returns to A and B (2 mins) and hands over flashlight to A
A and B cross (10 mins) and A hands over flashlight to D
D returns to C (1 min)
C and D cross (2 mins)

2 + 2 + 10 + 1 + 2 = 17.

But Dominique said as much here ...

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I think you'll find it's a bit more complicated than that ...

Lots of replies... I see the correct answer goes to Dominique with her solution. Well Done!!!

Also - A big thank you to everyone else!

Standings:
1. Jason Gee - 4 Points
2. Fred - 1 1/2 Point
3. The Gas Giant - 1 Point
4. JDWhale - 1 Point
5. Dominique - 1 Point
6. TBD...

Question 13: There exists a small town of 101 people in which John and Richard are running for mayor. Each person in the town (including the two running) cast their vote based on the toss of a fair coin. As the ballots are counted the results are reported vote by vote. The final result is 51 votes for Richard and 50 for John. What is the probability that as the votes were being counted Richard was always ahead?

Luke.

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- Luke.

Lots of replies... I see the correct answer goes to Dominique with her solution. Well Done!!!

Also - A big thank you to everyone else!

Standings:
1. Jason Gee - 4 Points
2. Fred - 1 1/2 Point
3. The Gas Giant - 1 Point
4. JDWhale - 1 Point
5. Dominique - 1 Point
6. TBD...

Question 13: There exists a small town of 101 people in which John and Richard are running for mayor. Each person in the town (including the two running) cast their vote based on the toss of a fair coin. As the ballots are counted the results are reported vote by vote. The final result is 51 votes for Richard and 50 for John. What is the probability that as the votes were being counted Richard was always ahead?

Luke.

Objection, m'lud! Can you please please explain where either of the alternative answers that I submitted 2 hours before Dominique (one of which proposed the same solution) were incorrect?

F.

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Lots of replies... I see the correct answer goes to Dominique with her solution. Well Done!!!

Also - A big thank you to everyone else!

Standings:
1. Jason Gee - 4 Points
2. Fred - 1 1/2 Point
3. The Gas Giant - 1 Point
4. JDWhale - 1 Point
5. Dominique - 1 Point
6. TBD...

Question 13: There exists a small town of 101 people in which John and Richard are running for mayor. Each person in the town (including the two running) cast their vote based on the toss of a fair coin. As the ballots are counted the results are reported vote by vote. The final result is 51 votes for Richard and 50 for John. What is the probability that as the votes were being counted Richard was always ahead?

Luke.

Objection, m'lud! Can you please please explain where either of the alternative answers that I submitted 2 hours before Dominique (one of which proposed the same solution) were incorrect?

F.

Fred is right. It's that my explanation is just "simpler" to follow.

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I'm only following this link: Question 13

Fred - You Wanna' Point? ;)

Luke.

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- Luke.

I'm only following this link: Question 13

Fred - You Wanna' Point? ;)

Luke.

Since points have as much purchasing power in Asda (WalMart) as cobblestones, not too concerned about that. Just wanted to understand where either of my solutions was wrong.

F.

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I'm only following this link: Question 13

Fred - You Wanna' Point? ;)

Luke.

Since points have as much purchasing power in Asda (WalMart) as cobblestones, not too concerned about that. Just wanted to understand where either of my solutions was wrong.

F.

Not wrong... no, no, no! Just... officially unofficial may I say... lol.

Luke.

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- Luke.

I concur that Fred got that point ;D (Uh-oh he's catching up.. better try another soon)

Q13 Answer is 1/101 I think,

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"Living by the wisdom of computer science doesn't sound so bad after all. And unlike most advice, it's backed up by proofs." -- Algorithms to live by: The computer science of human decisions.

I concur that Fred got that point ;D (Uh-oh he's catching up.. better try another soon)

Hiya Jason.....working on that new Astrokitty app yet? Or just takin' a breather since getting the SSE online?

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"Freedom is just Chaos, with better lighting." Alan Dean Foster

I concur that Fred got that point ;D (Uh-oh he's catching up.. better try another soon)

Hiya Jason.....working on that new Astrokitty app yet? Or just takin' a breather since getting the SSE online?

Well, back to my circuit analysis studies for a while, which makes me in math mode temporarily [Hence the recreational appearances here], I intend to give the project time to stabilise & iron out any hiccups prior to tampering with that, though I have had a peek at some of the source code.

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"Living by the wisdom of computer science doesn't sound so bad after all. And unlike most advice, it's backed up by proofs." -- Algorithms to live by: The computer science of human decisions.

I concur that Fred got that point ;D (Uh-oh he's catching up.. better try another soon)

Hiya Jason.....working on that new Astrokitty app yet? Or just takin' a breather since getting the SSE online?

I declare this maths thread fully Astrokitty compatible! *BSOD*

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- Luke.

I declare this maths thread fully Astrokitty compatible! *BSOD*

In case my edit got missed:

Q13 Answer is 1/101 I think

But it seemed really hard, so I may be wrong there...

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"Living by the wisdom of computer science doesn't sound so bad after all. And unlike most advice, it's backed up by proofs." -- Algorithms to live by: The computer science of human decisions.

OK... out of Fred's ability to poke fun at the smallest fixture or error I post ;-) I award him a half point! Well Done (and don't do it again! :D)

Onto a more serious matter...
Q13 is won by Jason Gee with the answer: 1/101. Well Done! 1 Point....

Standings:
1. Jason Gee - 5 Points
2. Fred - 2 Points
3. Gas Giant - 1 Point
4. JDWhale - 1 Point
5. Dominique - 1 Point
6. TBD...

Question 14 (Which I leave with you for the next 9 hours) 1/2 Point:
(23562*24/5)+(732*732/365.52)=

Luke.

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- Luke.

I concur that Fred got that point ;D (Uh-oh he's catching up.. better try another soon)

Hiya Jason.....working on that new Astrokitty app yet? Or just takin' a breather since getting the SSE online?

Well, back to my circuit analysis studies for a while, which makes me in math mode temporarily [Hence the recreational appearances here], I intend to give the project time to stabilise & iron out any hiccups prior to tampering with that, though I have had a peek at some of the source code.

Recreation is good.......methinks you have too little of it......don't know how you carry on at the pace you keep.
I you need any testing again, let me know....PM works, just yank me chain.......

But Joe will need to come up with some new knabench test WUs that will not take a couple of weeks to complete...LOL.

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"Freedom is just Chaos, with better lighting." Alan Dean Foster