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Octagon Send message Joined: 13 Jun 05 Posts: 1418 Credit: 5,250,988 RAC: 109
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Work has been done on how much mass one must start with to get a black hole as opposed to one of the other possible "corpses" like white drawfs and supernovae. I'm not sure what they are, but I think it was something on the order of 5 solar masses while in the main sequence (and about 2 solar masses when collapsing). Nothing with the mass of the Moon will naturally collapse into a black hole, but maybe a 5-solar-mass star crammed into the Moon's volume would? Sorry, I don't have the time for in-depth research right now to translate into qualitative terms. No animals were harmed in the making of the above post... much.
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Octagon Send message Joined: 13 Jun 05 Posts: 1418 Credit: 5,250,988 RAC: 109
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To replay what I've read about it (I'm sure you'll tell me if I'm wrong): This is mostly in line with what I've seen on it, except that it doesn't matter which of the virtual particle pair falls into the black hole, both have positive mass. A pair of virtual particles pop into existence, flying away from each other. The electrical attraction makes them slow to a stop then fall back into each other and annihilate. Think of it from a different perspective: what makes an antiparticle an antiparticle? It is spinning in the opposite direction. If you can picture a normal particle travelling backward in time, it would appear to have an opposite spin and thus be an antiparticle. Now imaging a particle moving in a tight circular orbit. Circles are two-dimensional. If one of the axes of that plane is the "time" axis, then from a typical three-dimensional viewpoint you will see the particle moving forward in time along a semicircle then the same particle moving backward in time along the second half of the circle. While the particle is moving backward in time, it appears to us as an antiparticle. There is apparently evidence to support the existence of these virtual particles. If the world line of a black hole's event horizon perturbs this happy little circling particle, it flies off and the black hole has lost a tiny bit of its energy in the process. We see the particle "come from nowhere" and call it Hawking Radiation (which has not been directly observed, but it neatly wraps up some conservation issues if it exists). I don't really understand why these particles would exist, and why they wouldn't just fall into the black hole. You'll have to ask Professor Hawking about that. No animals were harmed in the making of the above post... much.
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Sleestak Send message Joined: 22 Jun 01 Posts: 779 Credit: 857,664 RAC: 0
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Octagon Send message Joined: 13 Jun 05 Posts: 1418 Credit: 5,250,988 RAC: 109
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If you can show me a formulation for a black hole that takes into account matter ejection during the cooling process, I'll give it cosideration. If it only considers cooling radiation, it's not complete. I did a quick search and found this paper on hypercritical accretion leading up to the formation of a stellar mass black hole. I think it only applies to binary systems with one black hole and one star, but I didn't have enough time to digest the whole thing and make a qualitative case for it. The jist is that the gravity-induced inflow bats back anything ejected from the collapsing star. No animals were harmed in the making of the above post... much.
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Sleestak Send message Joined: 22 Jun 01 Posts: 779 Credit: 857,664 RAC: 0
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If you can show me a formulation for a black hole that takes into account matter ejection during the cooling process, I'll give it cosideration. If it only considers cooling radiation, it's not complete. That is an interesting paper. I plan on reading it again in closer detail but with the first initial read, it appears that the jets and outflows that they talk about are from the accretion disk and not the neutron star itself. The accretion disk being the part falling into the star. Although, they did make a mention of of outflows from the neutron star affecting the outflows from the inner disk. Alternatively, outflows may arise predominantly from the inner disk. In this case, the energy feedback into the common envelope from outflows originating deep in the neutron star potential well could be highly significant. So, it's given an honorable mention but not directly dealt with. TEAM LL |
Sleestak Send message Joined: 22 Jun 01 Posts: 779 Credit: 857,664 RAC: 0
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I think the problem is not that a theoretical black hole can't be stable. It very well could be stable. It's the activation energy to actually get to a black hole. ...........<E_activation energy>=huge ...............-- ............../..\\ ............./....\\ ............/......\\ .........../........\\--<E_blackhole> ........../ ........./ ......../ ......./ <E_matter> The point here is that if the black hole is stable, it's not enough to say it meets the requirements of the Schwarzchild blackhole or satisfies the metric. You have to get to it. The diagram above is to represent an activation energy needed to take some amount of matter at energy <E_matter> to <E_black hole>. The problem is getting that equation correct. There are too many possible variables to know for sure if it's correct. The reverse might be. ................<E_activation energy> ...................-- ................../..\\ ................./....\\ ................/......\\ .............../........\\ <E-blackhole>...\\ ..........................\\ ...........................\\ ............................\\ .............................<E_matter> The thing that would make a black hole stable is if the activation energy to blow it apart is higher than it's current energy even though the <E_matter> is a lower energy level. My assertion is that the <E_activation> has not been properly dealt with. The equations tend to point out that a black hole is theoretically stable, but if the activation energy is greater than the total energy of the universe, the point of the black hole being stable is moot because it'll never happen. Proving that it can be stable at 1000 solar masses is not proving that it can happen because the activation energy might simple be too high. Like Stephen Hawkings said himself, since you are not directly probing the black hole, you can never be sure that it ever really formed. If it looks like a duck, walks like a duck, it could still be a goose. TEAM LL |
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Hans Dorn Send message Joined: 3 Apr 99 Posts: 2262 Credit: 26,448,570 RAC: 0
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The "density" of a black hole (It's mass divided by it's Schwarzschild volume) evalutes to this: (1.8x10^16 g/cm^3) x (Msun / M)^2 Don't shoot me if this equation is wrong, I grabbed it from here. The density of a neutron star is about 3 x 10^14 g/cm^3 If we postulate that a neutron star won't collapse, no matter how massive it is, and look at one that is constantly picking up mass from a companion star, then this neutron star can only grow until it's mass M has reached the mass of a black hole with equal density. After this point it will vanish into a black hole: (1.8x10^16 g/cm^3) x (Msun / M)^2 = 3 x 10^14 g/cm^3 (Msun/M)^2 = 3 x 10^14 / 1.8x10^16 (Msun/M)^2 = 0.017 Msun/M = 0.129 M = 7.75 * Msun This transition is instantaneous and doesn't require an inifinitesimal activation energy since no creation of an infinitely small black hole is required for it to happen. Regards Hans P.S: This calculation assumes that the neutron star has uniform density. In reality it's core will be more dense and the collapse happens earlier and more violent. |
Sleestak Send message Joined: 22 Jun 01 Posts: 779 Credit: 857,664 RAC: 0
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You still have to explain the increase in density. When you increase the density, the kinetic energy/temperature that needs to be released will grow exponentially. Thus, you need a way to cool it so that it can collapse before it blows up or blows off too much matter. This is typically done with a radiation density but does not take into account matter dissipation. TEAM LL |
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Hans Dorn Send message Joined: 3 Apr 99 Posts: 2262 Credit: 26,448,570 RAC: 0
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You still have to explain the increase in density. When you increase the density, the kinetic energy/temperature that needs to be released will grow exponentially. Thus, you need a way to cool it so that it can collapse before it blows up or blows off too much matter. There would be no increase in density (as viewed from the outside). The newborn black hole has the same radius and density as the hypothetical neutron star. Once you're inside the Schwarzschild radius, things get weird. I don't even know if the neutron star would collapse once the Schwarzschild radius raises above it's surface. Maybe Octagon can add some insight here. Regards Hans P.S: Since matter and energy are equivalent, it wouldn't make a difference if things heat up inside the Schwarzschild radius while potential energy turns into heat. |
Sleestak Send message Joined: 22 Jun 01 Posts: 779 Credit: 857,664 RAC: 0
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Chandra solves black hole mystery The way in which black holes suck in matter from neighbouring stars is a fundamentally magnetic process and not just caused by gravity. That's the conclusion from new measurements of the X-rays emitted by the gas surrounding a nearby black hole in the Milky Way. Although predicted by theory over 30 years ago, this is the first time that this effect has been seen. The result -- based on measurements from the Chandra X-ray observatory -- could affect theories on how matter falls onto black holes and other compact objects (Nature 441 953). TEAM LL |
Sleestak Send message Joined: 22 Jun 01 Posts: 779 Credit: 857,664 RAC: 0
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You held the radius the same and packed more matter in. You have to account for the compression of that matter.
But they are different when you measure them and there is no reason to meausure just radiation and not measure the matter coming off. You cannot say, this much radiation came off and a black hole formed without taking into account how much matter spewed off because that could thwart the density/heat problem. It has to be dense enough and cool enough. TEAM LL |
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Hans Dorn Send message Joined: 3 Apr 99 Posts: 2262 Credit: 26,448,570 RAC: 0
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I guess that's the key point you're touching here :o) The "density" of a black hole (as seen from the outside) actually decreases as it's mass M grows: rho = (1.8x10^16 g/cm^3) x (Msun / M)^2 If you double the mass of a black hole by throwing stuff into it, it's density will decrease to 1/4. You can get black holes of arbitrarily low density by doing so. Regards Hans P.S: The surface temperature, as indicated by the Hawking radiation, also drops when a black hole grows. |
Sleestak Send message Joined: 22 Jun 01 Posts: 779 Credit: 857,664 RAC: 0
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1. you just started with a black hole. 2. the problem is to get to the black hole, not start with one. 3. Hawking radiation is not proven, and is only for black holes, not the formation of a black hole. 4. It's not enough to say it meets the requirements of the black hole. You have to make the transistion from the set density to the varying conditions of the black hole. 5. Neutron stars can't have more than 3xM_sun because at that point the degenerate neutron cloud stabilizing pressure cannot prevent collapse. Thus you have to some how magically get from M_n <(less than) 3xM_sun to your theoretical 7.75xM_sun. TEAM LL |
K3UZZ Send message Joined: 29 May 99 Posts: 175 Credit: 67,332 RAC: 0
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I'm really glad I clicked on the BlackHoles site you referenced...BUT, did you see that black holes is just one small part of HubbleSite.org...? The entire site is terrific. <---Richard Feynman Team Richard Feynman |
Octagon Send message Joined: 13 Jun 05 Posts: 1418 Credit: 5,250,988 RAC: 109
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Some models for black hole formation predict that the back hole is the interior remnant of a supernova (kind of like a "white dwarf and planetary nebula" on steroids). Presumably, these models assume any black hole we see today has either recaptured its castoff material, or is so old that its castoff material has already been assimilated into nearby stars and nebulae. That does seem a bit too convenient. Since neutron starts explode into supernovae due to runaway reactions that only take a fraction of a second, it is reasonable to deduce that neutrons stars that collapse into black holes also do so in a fraction of a second. The "average case" where a white dwatf simply cools into a black dwarf with no climax is predicted to take longer than the presumed age of the Universe (13.7 billion years). I saw presumed because I want to include Modified Steady State models of the Universe. If the Universe is orders of magnitude older than 13.7 billion years, black dwarves could account for some, but not all, of the observed actions attributed to black holes. No animals were harmed in the making of the above post... much.
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Sleestak Send message Joined: 22 Jun 01 Posts: 779 Credit: 857,664 RAC: 0
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Supposedly, although it's "stable" at 7.75 solar masses, to actually form a black hole in the first place, it takes 25 x M_{sun} that is 25 solar massses. If it's exploding at 3 solar masses how can one account for the the 22 solar masses disparity? You would need 9 of the largests neutron stars colliding at one moment in time. Do you have links to the models that you're talking about? TEAM LL |
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